Janitsu wrote:
Meiyjhe:
If X = 30 what is the meaning of life?
Then you must check the Urban dictionary and search for number 30
Change is gooooood
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Meiyjhe wrote:
pls u guise suck, A actually has a standard value, in the hexadecimal system.
In the hexadecimal numeric system, A = 10 in the decimal system. In the hexadecimal numeric system, 10 = 16 in the decimal system.
Thus 10 + 5 = 15, 16 + 5 = 21
10/21 = 0,476
Thus A/15 = 0,476
If A = 10 then we have 10/15, where the **** are you getting all the other numbers from?
A/15 = 10/15 = 0,67
Janitsu wrote:
If X = 30 what is the meaning of life?
Undefined.
"Moral justification is a powerful disengagement mechanism. Destructive conduct is made personally and socially acceptable by portraying it in the service of moral ends." - Albert Bandura
"Ultimately, if people lose their willingness to recognize that there are times in our history when legality becomes distinct from morality, we aren't just ceding control of our rights to government, but our futures." - Edward Snowden
"Ultimately, if people lose their willingness to recognize that there are times in our history when legality becomes distinct from morality, we aren't just ceding control of our rights to government, but our futures." - Edward Snowden
Searz wrote:
If A = 10 then we have 10/15, where the **** are you getting all the other numbers from?
Pls. I thought u wuld understand out of all people.
A is a hexadecimal number. 10 in this case is a decimal number.
If you divide A/15 (where A is a hexadecimal number), that means that 15 is also a hexadecimal number (since it is in the same calculation). Hexadecimal 15 =/= decimal 15. Hexadecimal 15 = decimal 21.
Thus A/15 hexadecimal = 10/21 decimal. 10/21 = 0,476.
I rest my case >:)
Change is gooooood
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Je suis le bee ~ Meiyjhe ~ |
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sinh3xcosh2x = (sinhx)(cosh2x-1)(cosh2x)
=sinhx(cosh4x-cosh2x)
sub in u = coshx
du/dx = sinhx, dx=du/sinhx
(sinhx)(u4-u2) du/sinhx | sinhx's cancel out
integrate u4-u2 du = (1/5)u5-(1/3)u3 + c
replace u
answer is (1/5)cosh5x-(1/3)cosh3x + c
which is equivalent to the answer you obtained from Wulfram.
you would not want to do that by parts
=sinhx(cosh4x-cosh2x)
sub in u = coshx
du/dx = sinhx, dx=du/sinhx
(sinhx)(u4-u2) du/sinhx | sinhx's cancel out
integrate u4-u2 du = (1/5)u5-(1/3)u3 + c
replace u
answer is (1/5)cosh5x-(1/3)cosh3x + c
which is equivalent to the answer you obtained from Wulfram.
you would not want to do that by parts
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