Need High School Math (Algebra ~ Calculus) Help?

[quote=Kinen]@GMD, don't we get anything for humouring him? This would never have happened without our contributions.[/quote]

[quote=Meiyjhe][quote=Janitsu] Meiyjhe: If X = 30 what is the meaning of life? [/quote] [url=A series of tasks and duties between blowjobs.]Then you must check the Urban dictionary and search for number 30[/url][/quote]

[quote=Janitsu]A%20series%20of%20tasks%20and%20duties%20between%20blowjobs.?[/quote]

[quote=Meiyjhe][quote=Janitsu] A%20series%20of%20tasks%20and%20duties%20between%20blowjobs.? [/quote] Exactly[/quote]

[quote=Pheyniex][quote=Kinen] Integrate sinh[sup]3[/sup]xcosh[sup]2[/sup]x [/quote] http://www.wolframalpha.com/ integral sinh^3(x) cosh^2(x) dx = 1/30 cosh^3(x) (3 cosh(2 x)-7)+constant[/quote]

[quote=Searz][quote=Meiyjhe] pls u guise suck, A actually has a standard value, in the hexadecimal system. In the hexadecimal numeric system, A = 10 in the decimal system. In the hexadecimal numeric system, 10 = 16 in the decimal system. Thus 10 + 5 = 15, 16 + 5 = 21 10/21 = 0,476 Thus A/15 = 0,476[/quote] If A = 10 then we have 10/15, where the fuck are you getting all the other numbers from? A/15 = 10/15 = 0,67 [quote=Janitsu] If X = 30 what is the meaning of life?[/quote] Undefined.[/quote]

[quote=Meiyjhe][quote=Searz] If A = 10 then we have 10/15, where the fuck are you getting all the other numbers from? [/quote] Pls. I thought u wuld understand out of all people. A is a hexadecimal number. 10 in this case is a decimal number. If you divide A/15 (where A is a hexadecimal number), that means that 15 is also a hexadecimal number (since it is in the same calculation). Hexadecimal 15 =/= decimal 15. Hexadecimal 15 = decimal 21. Thus A/15 hexadecimal = 10/21 decimal. 10/21 = 0,476. I rest my case >:)[/quote]

[quote=Kinen][quote=Pheyniex] [quote=Kinen] Integrate sinh[sup]3[/sup]xcosh[sup]2[/sup]x [/quote] http://www.wolframalpha.com/ integral sinh^3(x) cosh^2(x) dx = 1/30 cosh^3(x) (3 cosh(2 x)-7)+constant [/quote] Can't do that in an exam, cheater.[/quote]

[quote=Pheyniex][quote=Kinen] [quote=Pheyniex] [quote=Kinen] Integrate sinh[sup]3[/sup]xcosh[sup]2[/sup]x [/quote] http://www.wolframalpha.com/ integral sinh^3(x) cosh^2(x) dx = 1/30 cosh^3(x) (3 cosh(2 x)-7)+constant [/quote] Can't do that in an exam, cheater. [/quote] that wasn't a rule in this thread. you'd have to integrate by parts about 3 or 4 consecutive times. [url]http://en.wikipedia.org/wiki/Integration_by_parts[/url][/quote]

[quote=Kinen]sinh[sup]3[/sup]xcosh[sup]2[/sup]x = (sinhx)(cosh[sup]2[/sup]x-1)(cosh[sup]2[/sup]x) =sinhx(cosh[sup]4[/sup]x-cosh[sup]2[/sup]x) sub in u = coshx du/dx = sinhx, dx=du/sinhx (sinhx)(u[sup]4[/sup]-u[sup]2[/sup]) du/sinhx | sinhx's cancel out integrate u[sup]4[/sup]-u[sup]2[/sup] du = (1/5)u[sup]5[/sup]-(1/3)u[sup]3[/sup] + c replace u answer is (1/5)cosh[sup]5[/sup]x-(1/3)cosh[sup]3[/sup]x + c which is equivalent to the answer you obtained from Wulfram. you would not want to do that by parts[/quote]