Need High School Math (Algebra ~ Calculus) Help?

[quote=Searz][quote=Meiyjhe] Pls. I thought u wuld understand out of all people. A is a hexadecimal number. 10 in this case is a decimal number. If you divide A/15 (where A is a hexadecimal number), that means that 15 is also a hexadecimal number (since it is in the same calculation). Hexadecimal 15 =/= decimal 15. Hexadecimal 15 = decimal 21.[/quote] Your entire conclusion hinges on the fact that 15 is a hexadecimal number, but I don't think it is. If you would have defined it as F - the corresponding hexadecimal number - then that is obviously a hexadecimal number. But in this case it was defined as 15, not F, and as such I'm treating it as a decimal number.[/quote]

[quote=Meiyjhe][quote=Searz] Your entire conclusion hinges on the fact that 15 is a hexadecimal number, but I don't think it is. If you would have defined it as F - the corresponding hexadecimal number - then that is obviously a hexadecimal number. But in this case it was defined as 15, not F, and as such I'm treating it as a decimal number. [/quote] Yup, but A/15 as a decimal calculation, it means "unknown value"/15, thus no possible outcome without knowing A. However, if it is a hexadecimal calculation, it means 10/21 in decimal numbers, which actually can be calculated :3 So if you were to create an answer based on the information you had, the only way to get an actual legit answer (as far as I know of) is by saying that it is a hexadecimal calculation. If we would say that it is a decimal calculation, then the answer is: [quote=Toshabi] actually syntax error. Thanks for nothing, idiots. [/quote] :D[/quote]

[quote=Vapora Dark][quote=GrandmasterD] Seriously, two pages about a Toshabi troll; he does deserve a prize for this. [/quote][/quote]

[quote=YeaISupport]Holy fricking cow! So many questions! I am back guys. Wait for the answers![/quote]

[quote=IShouldGetALife]Sucks being a year 10 we don't learn this shit yet D:[/quote]

[quote=YeaISupport][quote=Kinen] Integrate sinh[sup]3[/sup]xcosh[sup]2[/sup]x [/quote] Holy cow XD Hyperbolic equation. To refer, it's this: [url=http://www.math24.net/integration-of-hyperbolic-functions.html]List of hyperbolic integration[/url] And, for this, you have to do [url=https://www.math.ucdavis.edu/~kouba/CalcTwoDIRECTORY/usubdirectory/]u-substitution.[/url] So... looking at the steps: [rule] Step 1: Decide your [i]u[i] and [i]du[i]. I am going to pick cosh[sub]2[/sub] x as my [i]u[/i]. [i]u[i] = cosh[sub]2[/sub] x Now, to find your [i]du[/i] for u-substitution, you have to differentiate the [i]u[/i] [i]du[/i] = 2sinh x * sinh x dx (You use the chain rule to get this derivative.) [rule] Step 2: Substitute it back in. From now on, it's easy substitution! Tell me if you need more help![/quote]

[quote=YeaISupport][quote=Pheyniex] [quote=Kinen] [quote=Pheyniex] [quote=Kinen] Integrate sinh[sup]3[/sup]xcosh[sup]2[/sup]x [/quote] http://www.wolframalpha.com/ integral sinh^3(x) cosh^2(x) dx = 1/30 cosh^3(x) (3 cosh(2 x)-7)+constant [/quote] Can't do that in an exam, cheater. [/quote] that wasn't a rule in this thread. you'd have to integrate by parts about 3 or 4 consecutive times. [url]http://en.wikipedia.org/wiki/Integration_by_parts[/url] [/quote] You just have to use [i]u[/i]-substitution. :3[/quote]

[quote=screwblum]I don't start school until Wednesday and I can already tell this is going to suck. My brain went to mush over the summer.[/quote]