NinjaGinge
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Credit goes to JEFFY40HANDS for this godly imposing Viktor
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NinjaGinge
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ok matrix is pretty messy but came out with...
x1 = 2a-b+2c
x2 = 2c-a-1
x3 = c
x4 = b-3c-a+1
I hope I didnt herp derp anywhere in there
x1 = 2a-b+2c
x2 = 2c-a-1
x3 = c
x4 = b-3c-a+1
I hope I didnt herp derp anywhere in there
Thanks goes to JEFFY40HANDS for a gorgeous Karma sig
Hey, you should help me on acquiring Medieval Twitch!! :D
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ShadowNet
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That looks like stuff I had last year, when I studied maths at university.
The first one is like this:
(1 0 1 1 | a+1)
(1 1 -1 1 | 0)
(0 1 1 1 | b+2)
(1 1 1 1 | 2c)
It should look like a big bracket, if you get what I mean.
Then you try to get a 1 at the top left, and a 0 on all the other places vertical to that.
So first step:
Do nothing with line 1 (you want the 1 at the top left), take line 2 and substract line 1 from it (so you get a 0 at the first place), do nothing with line 3 (there already is a 0 at the first place) and take line 4 and substract line 1 from it (to get another 0). Keep on going until you can no longer do it, and then the answer should pop up.
I believe det(An) is like (-c-2)^n + ((-c-2)^n)^n - ((-c-2)*(a+1)^n)^n .
Basically you take the diagonal from top left until bottom right, and multiply all terms. Then move 1 to the right (if you can't, move all the way to the left) and keep on going until you reach the last one (let's call it f). Then you take the diagonal from top right to bottom left, and multiply all terms. Then move one to the right and repeat until you are done (let's call it g). Then f-g and done ;)
Well I hope this helps ;D
The first one is like this:
(1 0 1 1 | a+1)
(1 1 -1 1 | 0)
(0 1 1 1 | b+2)
(1 1 1 1 | 2c)
It should look like a big bracket, if you get what I mean.
Then you try to get a 1 at the top left, and a 0 on all the other places vertical to that.
So first step:
Do nothing with line 1 (you want the 1 at the top left), take line 2 and substract line 1 from it (so you get a 0 at the first place), do nothing with line 3 (there already is a 0 at the first place) and take line 4 and substract line 1 from it (to get another 0). Keep on going until you can no longer do it, and then the answer should pop up.
I believe det(An) is like (-c-2)^n + ((-c-2)^n)^n - ((-c-2)*(a+1)^n)^n .
Basically you take the diagonal from top left until bottom right, and multiply all terms. Then move 1 to the right (if you can't, move all the way to the left) and keep on going until you reach the last one (let's call it f). Then you take the diagonal from top right to bottom left, and multiply all terms. Then move one to the right and repeat until you are done (let's call it g). Then f-g and done ;)
Well I hope this helps ;D
DuffTime wrote:
ok ok plz carry me omg
i was only waiting for you to ask
Temzilla wrote:
Too hot to be icecream.
Luther3000 wrote:
He looks like a hair gel advert on legs
Toshabi wrote:
Icecreamy, with hair as slick and smooth as the ocean waves of Cocobana
NinjaGinge
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thanks ^_^. If I feel inspired after I do my work i'll tackle that det one. Its got a pattern to it so it MIGHT not be disgusting. lol
Credit goes to JEFFY40HANDS for this godly imposing Viktor
Hey, you should help me on acquiring Medieval Twitch!! :D
http://signup.leagueoflegends.com/?ref=507f1031d2ab3250817727
Hey, you should help me on acquiring Medieval Twitch!! :D
http://signup.leagueoflegends.com/?ref=507f1031d2ab3250817727
I decided to calculate the answer to the first one, I come up with
x1 = -b-2c-2
x2 = -a+2c-1
x3 = c
x4 = a+b+c+3
So it's slightly different from the answer from NinjaGinge, I guess you should calculate it yourself :D
x1 = -b-2c-2
x2 = -a+2c-1
x3 = c
x4 = a+b+c+3
So it's slightly different from the answer from NinjaGinge, I guess you should calculate it yourself :D
DuffTime wrote:
ok ok plz carry me omg
i was only waiting for you to ask
Temzilla wrote:
Too hot to be icecream.
Luther3000 wrote:
He looks like a hair gel advert on legs
Toshabi wrote:
Icecreamy, with hair as slick and smooth as the ocean waves of Cocobana
NinjaGinge
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<Editor>
IceCreamy wrote:
I decided to calculate the answer to the first one, I come up with
x1 = -b-2c-2
x2 = -a+2c-1
x3 = c
x4 = a+b+c+3
So it's slightly different from the answer from NinjaGinge, I guess you should calculate it yourself :D
CURSES. now I'll have to check my work when I come back from dinner. lol XD
Credit goes to JEFFY40HANDS for this godly imposing Viktor
Hey, you should help me on acquiring Medieval Twitch!! :D
http://signup.leagueoflegends.com/?ref=507f1031d2ab3250817727
Hey, you should help me on acquiring Medieval Twitch!! :D
http://signup.leagueoflegends.com/?ref=507f1031d2ab3250817727
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Solve the system of equations:
unless im mistaken because i didnt look at it too hard that det is disgusting. so im ignoring it.
will solve matrix though